逐日AI

面试题库

共 328 题,当前筛选 2 题。

标签
还有 126 个标签
#agent-loop2#api-design2#chunking2#cost-tradeoff2#debugging2#error-handling2#hybrid-search2#llm-as-judge2#multi-agent2#multi-hop2#oauth2#operations2#pipeline-design2#prompt-caching2#rag2#recall2#retrospective2#retry2#scheduling2#sse2#tool-permissions2#trade-offs2#access-control1#agentic-rag1#agents-sdk1#analytics1#architecture-review1#behavioral1#budget-control1#caching1#cancellation1#checkpointing1#circuit-breaker1#citation-verification1#client1#client-integration1#coding-agent1#compaction1#compliance1#concurrency1#confused-deputy1#context-engineering1#contextual-retrieval1#copyright1#correctness1#cost-control1#customer-support1#data-quality1#database1#deployment1#distribution1#embedding-migration1#error-propagation1#escalation1#evidence1#faithfulness1#fallback1#feedback-loop1#fencing-token1#filter-pushdown1#filtering1#framework-design1#graph-rag1#guardrails1#handoff1#image-generation1#integration1#iterative-scan1#json-parsing1#labeling1#latency1#latency-budget1#least-privilege1#long-context1#long-session1#long-term-memory1#mcp1#message-bus1#methodology1#model-migration1#multi-tenancy1#notifications1#ocr1#offline-testing1#project-storytelling1#protocol-versions1#quality1#query-rewriting1#rate-limiting1#reconnect1#refusal1#replay1#reproducibility1#rerank1#resume1#retrieval1#risk-assessment1#rollout1#routing1#runtime1#safety1#scaling1#self-introduction1#split-brain1#state-management1#state-persistence1#statelessness1#stdio-transport1#storytelling1#subagent1#subagents1#subscriptions1#test-strategy1#thresholds1#timezone1#token-accounting1#tool-design1#tool-schema1#tools1#trust-boundary1#ux1#verification1#versioning1#workflow-design1#workflow-engine1#zero-downtime1

30 天从前端工程师到 Agent 工程师

D13 cron 调度(中心调度→stream 投递)+ 成本计量(token→USD 台账、usage report)

  • 怎么保证一个 cron 任务不会被重复投递或重复执行?幂等键应该怎么构造?How do you keep a cron job from being published or executed twice, and how should the idempotency key be built?
    国内高频海外高频深入#idempotency#scheduling#distributed-systems

    分析过程 · 先想清楚再作答

    1. 题眼在「投递」和「执行」是两件事。很多人只答一半:要么只说消费组保证一条消息一个消费者(那只挡住了执行侧的重复),要么只说加锁(那只挡住了投递侧,还挡不干净)。完整答案要说清两侧各自的重复来源,以及一个能同时兜住的兜底。
    2. 先拆重复的来源:投递侧的重复来自多个调度器实例、调度器重启后的补发重放、以及消息总线本身的至少一次语义;执行侧的重复来自 Worker 处理到一半崩溃后消息被 XAUTOCLAIM 转交给别人。这两类重复用不同手段挡效率完全不同。
    3. 再给核心结论:不要用分布式锁去做互斥,用数据层的唯一约束做去重。原因是锁只能提供「大概率互斥」——租约到期而前任进程其实只是 GC 卡住的那一瞬间,两个调度器都会认为自己持有,各发一次;而唯一约束是在最终落库那一步判断的,无论上游发了几次,任务表里只会多一行。能在唯一约束上解决的问题,不要升级成分布式协调问题。
    4. 然后回答幂等键怎么构造,这是最容易翻车的一步:键必须是「任务 id 加计划触发的那一分钟」,绝不能用当前时刻。两个调度器实例的时钟不可能对齐到毫秒,一个在 09:00:00.120 醒来、另一个在 09:00:00.480 醒来,用 now 算出来的键不一样,去重完全失效。把秒和毫秒截掉之后,无论谁在这一分钟里的哪一刻醒来,算出的键都是同一个字符串。落到代码上就是 insert 加 on conflict do nothing,冲突说明已经有人建过这次执行,直接 ack 掉不执行。
    5. 补一句作用范围:这套只保证「同一个触发点只产生一次执行」,不保证「执行内部的副作用只发生一次」。如果这次执行要发短信、要扣款,那些副作用还得各自带自己的幂等键,因为 Worker 可能在发完短信之后、写完状态之前崩掉。这一层区分是加分项。
    6. 可以预期的追问:那漏发怎么办?答宁可多发不可少发——调度器启动时回看最近 N 分钟逐分钟重放,重复投递被幂等键吃掉。at-least-once 加幂等是分布式系统里最省心的一组搭配,反过来先追求 exactly-once 再补幂等,通常两头都做不好。

    How to reason about it · think before answering

    1. The hinge is that publishing and executing are two separate problems. Most candidates answer half: either only the consumer group (which stops duplicate execution) or only a lock (which stops duplicate publishing, and imperfectly). A complete answer names the duplicate sources on both sides plus one backstop that covers both.
    2. Enumerate the sources: duplicate publishes come from multiple scheduler instances, from replay after a scheduler restart, and from the bus's own at-least-once semantics. Duplicate executions come from a worker crashing mid-processing and the message being reclaimed by another consumer. The two need different treatment.
    3. State the core conclusion: do not reach for a distributed lock, use a uniqueness constraint in the data layer. A lease only gives you probable mutual exclusion — in the instant when the TTL expires while the previous holder is merely stuck in GC, both schedulers believe they hold it and both publish. A uniqueness constraint is evaluated at the final insert, so no matter how many times upstream published, the table gains exactly one row. Do not escalate a problem solvable by a constraint into a distributed coordination problem.
    4. Then the key construction, which is where people fail: the key must be the task id plus the scheduled minute, never the current instant. Two scheduler clocks never align to the millisecond; one wakes at 09:00:00.120 and the other at 09:00:00.480, so keys built from now differ and dedup collapses. Truncate seconds and milliseconds and every instance computes the same string for that minute. In code this is an insert with on conflict do nothing; a conflict means the execution already exists, so ack the message and skip.
    5. Scope it honestly: this guarantees one execution per trigger point, not that side effects inside the execution happen once. If the run sends an SMS or charges a card, those side effects need their own idempotency keys, because the worker can crash after sending and before writing status. Making that distinction earns points.
    6. Expect: what about missed triggers? Prefer over-publishing to under-publishing — replay the last N minutes at startup and let the idempotency key absorb duplicates. At-least-once plus idempotency is the easiest combination in distributed systems; chasing exactly-once first and adding idempotency later usually achieves neither.

    答题要点

    • 投递重复和执行重复是两件事:前者来自多调度器实例、重启重放和总线的至少一次语义,后者来自 Worker 崩溃后消息被转交
    • 用数据层唯一约束去重,不要用分布式锁互斥:租约过期而前任还活着的瞬间两个调度器都会各发一次,而唯一约束在落库那一步只放行一条
    • 幂等键必须是任务 id 加计划触发的那一分钟,不能用当前时刻——两个实例的醒来时刻永远不同,用 now 会让去重完全失效
    • 落到代码上是 insert 加 on conflict do nothing,冲突就直接 ack 不执行
    • 这只保证一个触发点一次执行,执行内部的发短信、扣款等副作用要各自带幂等键;宁可多发不可少发,靠 at-least-once 加幂等兜底

    Key points

    • Duplicate publishing and duplicate execution are separate: the former comes from multiple schedulers, restart replay and at-least-once delivery; the latter from a crashed worker's message being reclaimed
    • Dedupe with a database uniqueness constraint rather than a distributed lock: when a lease expires while the holder is only GC-stalled, both schedulers publish, whereas the constraint admits exactly one row
    • Build the key from the task id plus the scheduled minute, never the current instant — instances never wake at the same millisecond, so a now-based key defeats dedup entirely
    • In code this is an insert with on conflict do nothing; on conflict, ack the message and skip execution
    • This guarantees one execution per trigger, not once-only side effects — SMS or payments inside the run need their own keys; prefer over-publishing and let at-least-once plus idempotency absorb it

D14 部署运维:compose 多 worker、心跳、健康检查、优雅停机、dev/prod 隔离;W2 复盘

  • 系统设计:请设计一个 IM Agent 平台——用户在即时通讯软件里和一个 AI 助手对话,助手能调用工具、记住长期偏好、还能定时主动推送。要求支撑十万日活。System design: design an IM agent platform where users chat with an AI assistant inside a messaging app. The assistant calls tools, remembers long-term preferences, and proactively pushes scheduled messages. Target 100k daily active users.
    国内高频海外高频深入#system-design#distributed-systems#cost#operations

    分析过程 · 先想清楚再作答

    1. 先别画图。系统设计题最常见的死法是听完就开始画框,二十分钟后面试官发现你解的是另一道题。花三到五分钟问清四件事:一是流量形状(十万日活对应多少并发会话、峰谷比多少),二是延迟要求(首字节要多快,是否必须流式),三是工具的性质(只读查询还是有写操作和副作用),四是主动推送的合规边界(能不能在深夜推、每天上限几条)。这四个答案会实质改变架构,问它们本身就是分数。
    2. 然后给主干,一句话先定形状:**接入层无状态、消息总线解耦、Worker 有状态且按用户分片、状态全在数据库**。接着按数据流走一遍:IM 平台的 webhook 打到接入层,接入层只做鉴权、限流、落库、投递四件事,立刻返回 202;执行侧从总线取活、跑 Agent 循环、把输出片段回传;主动推送由一个中心调度器按时间投递进同一条总线。**关键论点是接入层耗时确定、执行层耗时不确定,把它们放在一个进程里意味着一次慢的模型调用会占住一个本该毫秒级返回的连接**——这是整道题的立论基础,要主动说出来。
    3. 再逐个模块给出选择和理由。存储:sessions / runs / messages 三张表,runs 单独存在是因为只有它能回答「这次到底跑完没有」,幂等靠 runs 上的唯一约束而不是先查后插。总线:Redis Streams 的消费组做分摊,语义是至少一次,恰好一次靠消费端幂等做出来;反复失败的消息投递三次后进死信流。顺序:消费组的分配单位是一条消息而业务要求的串行单位是一个用户,所以按 userId 哈希到固定数量分片,每个分片同一时刻只有一个 Worker 持有租约。记忆:pgvector 存 embedding,检索包成一个工具交给模型自己决定要不要查,且不给它身份参数——身份只能来自会话。
    4. 主动推送这一块要单独讲透,因为它是这道题区别于普通聊天服务的地方。中心调度器命中时间点后只投一条消息,执行侧照旧;幂等键锚在「计划触发的那一分钟」,所以调度器崩溃重启后回看重放不会重复推送。合规上要有时区、静默时段、每日上限三道闸,而且这三道闸必须在投递前判断而不是在推送时判断——否则你已经花了模型调用的钱才发现不该推。
    5. 然后主动给出容量和成本的数字感,这是高级候选人的分水岭。十万日活、人均十轮对话是一百万次模型调用;按输入输出各一千 token、每百万 token 输入 0.15 美元输出 0.60 美元估算,一天大约七百五十美元。这个数字立刻推出三件事必须做:token 用量要按调用记账并换算成美元(否则你无法定位是哪个用户或哪个功能在烧钱)、要有分层降级(超预算的用户切便宜模型而不是直接拒绝)、以及上下文长度是主要成本杠杆(所以要压缩历史、控制检索条数)。
    6. 最后收在可运维性上,也就是这一周的落点:多副本部署、心跳发现假死、就绪探针只查自己必需的依赖、优雅停机让发版不掐断对话、dev 与 prod 用键名前缀隔离。**每个机制都要配一句「它失效时会怎样」**——租约会脑裂所以要有自杀规则和护栏令牌、心跳会误判所以面板转红只告警不自动摘流量、停机会超时所以等待要有上限。说不出失效模式的机制,面试官会认为你只是读过。
    7. 可以预期的追问,按出现频率排:单点在哪(调度器无状态可重启,Redis 和 Postgres 靠托管服务的主备);怎么灰度(新旧 Worker 同时在线,靠消息里的版本字段决定走哪套提示词);用户在助手回复中途又发一句怎么办(三十秒内的改口合并进同一次执行,而不是并发开两个);成本再降一半怎么做(缓存高频问答、压缩历史、把简单意图路由到小模型)。

    How to reason about it · think before answering

    1. Do not start drawing. The most common way to fail a design question is to hear the prompt and immediately sketch boxes, only for the interviewer to realise twenty minutes later that you solved a different problem. Spend three to five minutes on four questions: traffic shape (how many concurrent sessions does 100k DAU imply, and what is the peak-to-trough ratio), latency (how fast must first byte be, is streaming required), the nature of the tools (read-only lookups, or writes with side effects), and the compliance boundary on proactive pushes (may you push at night, what is the daily cap). All four change the architecture materially, so asking them is itself worth points.
    2. Then state the trunk in one sentence: stateless ingress, a message bus for decoupling, stateful workers sharded by user, all state in the database. Walk the data flow: the messaging platform's webhook hits ingress, which does only auth, rate limiting, persistence and publish, and returns 202 immediately; the execution side pulls work, runs the agent loop, and streams output fragments back; proactive pushes come from a central scheduler publishing onto the same bus. The load-bearing argument is that ingress latency is bounded while execution latency is not, so putting them in one process means one slow model call occupies a connection that should have returned in milliseconds — say this out loud, it is the premise of the whole answer.
    3. Then justify each module. Storage: sessions, runs and messages, with runs existing separately because only it can answer whether this attempt actually finished; idempotency comes from a unique constraint on runs, not from check-then-insert. Bus: Redis Streams consumer groups for fan-out, at-least-once semantics, with exactly-once manufactured by consumer-side idempotency, and messages that fail three times moved to a dead-letter stream. Ordering: the consumer group's unit of assignment is one message while the business requires serialisation per user, so hash userId into a fixed set of shards and let exactly one worker hold each shard's lease. Memory: embeddings in pgvector, retrieval wrapped as a tool the model chooses to call, with no identity parameter — identity only ever comes from the session.
    4. Treat proactive push as its own section, because it is what separates this from an ordinary chat service. The central scheduler publishes one message on a time match and the execution side is unchanged; the idempotency key is anchored to the scheduled minute, so replaying after a scheduler restart cannot double-send. For compliance you need timezone, quiet hours and a daily cap — and all three must be evaluated before publishing rather than at send time, or you have already paid for the model call before discovering you should not have pushed.
    5. Then volunteer capacity and cost numbers, which is what separates senior candidates. 100k DAU at ten turns each is a million model calls; at roughly a thousand tokens in and out, with input at $0.15 and output at $0.60 per million tokens, that is about $750 a day. That number immediately implies three requirements: meter token usage per call and convert to dollars (otherwise you cannot tell which user or feature is burning money), build tiered degradation (push over-budget users to a cheaper model rather than refusing them), and recognise that context length is the dominant cost lever (so compress history and cap retrieved items).
    6. Land on operability, which is this week's payoff: multiple replicas, heartbeats to surface zombies, readiness probes that only check their own hard dependencies, graceful shutdown so deploys do not cut conversations, and dev/prod isolation via key prefixes. Pair every mechanism with what happens when it fails — leases can split-brain so you need a self-fencing rule and fencing tokens, heartbeats produce false positives so a red dashboard alerts a human rather than auto-draining, shutdown can time out so the wait needs a ceiling. A mechanism without a stated failure mode reads as something you only read about.
    7. Expect, in rough order of frequency: where are the single points (the scheduler is stateless and restartable; Redis and Postgres rely on managed primary/replica); how do you roll out safely (old and new workers coexist and a version field in the message selects the prompt set); what if the user sends another message mid-reply (merge a change of mind within thirty seconds into the same execution rather than running two concurrently); and how would you halve the cost (cache frequent answers, compress history, route simple intents to a smaller model).

    答题要点

    • 先用三到五分钟问清四件事:流量形状、延迟要求、工具是否有副作用、主动推送的合规边界——它们会实质改变架构
    • 主干一句话:接入层无状态、消息总线解耦、Worker 有状态且按用户分片、状态全在数据库;立论是接入层耗时确定而执行层不确定
    • 存储 sessions / runs / messages 三张表,幂等靠 runs 上的唯一约束;总线用 Redis Streams 消费组,至少一次加消费端幂等,三次失败进死信
    • 顺序靠 userId 哈希分片加租约:消费组的分配单位是一条消息,而业务要求的串行单位是一个用户
    • 记忆用 pgvector 并包成工具交给模型自己决定是否检索,不给身份参数——身份只能来自会话
    • 主动推送由中心调度器投递,幂等键锚在计划触发的那一分钟;时区、静默时段、每日上限三道闸必须在投递前判断
    • 给出成本数字感:十万日活人均十轮约一百万次调用、一天约七百五十美元,由此推出计量记账、分层降级、压上下文三件事
    • 收在可运维性:多副本、心跳查假死、就绪探针只查自己的依赖、优雅停机、dev/prod 前缀隔离
    • 每个机制都配一句失效模式:租约会脑裂、心跳会误判、停机会超时——说不出失效模式等于只是读过

    Key points

    • Spend three to five minutes clarifying four things: traffic shape, latency targets, whether tools have side effects, and the compliance boundary on proactive pushes
    • State the trunk in one sentence: stateless ingress, bus for decoupling, stateful workers sharded by user, all state in the database — premised on bounded ingress latency versus unbounded execution latency
    • Storage is sessions/runs/messages with idempotency from a unique constraint on runs; the bus is Redis Streams consumer groups, at-least-once plus consumer idempotency, dead-lettering after three failures
    • Ordering comes from hashing userId into shards plus leases: the consumer group assigns per message while the business serialises per user
    • Memory is pgvector exposed as a tool the model may call, with no identity parameter — identity comes only from the session
    • Proactive push flows through a central scheduler with the idempotency key anchored to the scheduled minute; timezone, quiet hours and daily caps are enforced before publishing
    • Bring numbers: 100k DAU at ten turns is ~1M calls and ~$750/day, which implies metering, tiered degradation, and context length as the main cost lever
    • Land on operability: replicas, heartbeats for zombies, readiness probes scoped to own dependencies, graceful shutdown, dev/prod prefix isolation
    • Pair each mechanism with its failure mode — leases split-brain, heartbeats false-positive, shutdown times out; a mechanism without one reads as book knowledge