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流式接口的客户端断线重连后,怎么做到既不丢片段也不重复?After a streaming client reconnects, how do you deliver every missed chunk exactly once — no gaps, no duplicates?
国内高频海外高频深入#sse#idempotency#reconnect分析过程 · 先想清楚再作答
- 「不丢」和「不重复」要分开答。只答一半的人很多:说了从库里补发(不丢),却没说重叠部分怎么去重(不重复)。
- 推导链很短:客户端知道自己最后收到的编号 → 它重连时把这个编号带回来 → 服务端从下一号开始给 → 前提是编号连续不跳号。所以能不能重连,取决于当初有没有把序号设计成从 0 开始、连续、单调。序号一旦是时间戳或随机 id,这条链第一步就断了。
- 然后给三步实现和各自的坑:第一步换算,带回来的是「最后收到」的那一号,要加一,少加一重复一帧、多加一丢一个字,这是整段逻辑里唯一的算术也最常写错;第二步先从持久化里回放缺的部分,因为库里一定是全的;第三步再接上还在流动的那条流,两边必然重叠,靠「小于当前指针的一律丢弃」去重——幂等回放的全部秘密就是这一次比较。
- 这里要点出为什么必须双写:片段既进流也进库。只有流,重连时早期片段已被消费掉;只有库,就得轮询查库,首字延迟从几十毫秒涨到几百毫秒。代价是写放大,一次回答几百个片段就是几百行,生产里按批落库(每几十个片段或每两百毫秒一次)。
- 对齐一下协议细节:浏览器原生的事件源会自动把上次的编号放进重连请求头带回来;但大模型接口通常要用 POST,原生事件源只能发 GET,所以真实前端多是手写解析,重连时要自己把编号带上——这个细节能证明你真接过前端。
- 可以预期的追问:回放要保留多久?必须给两个边界——保留期(逐片段的行只对最近若干小时的执行保留,之后归档成一整条完整回复并删掉碎行)和回放上限(一次重连最多回放多少片段,超了就一次性发完整文本而不是逐字重演)。不定这两条,那张表会变成全库最大且 99% 的行写完十秒后再没人读。
How to reason about it · think before answering
- Answer 'no gaps' and 'no duplicates' separately. Plenty of candidates cover only the first — they backfill from storage but never say how the overlap is deduplicated.
- The chain is short: the client knows the last id it received, it sends that id back on reconnect, the server resumes from the next one — and all of that requires contiguous, monotonic numbering. Whether resumption is possible at all was decided when you chose the sequence scheme; timestamps or random ids break the chain at step one.
- Then the three steps and their individual traps. Convert: the client reports the last id it *received*, so add one — off by minus one repeats a frame, off by plus one drops a character, and this is the only arithmetic in the whole flow and the most commonly wrong line. Replay: read the missing range from durable storage, which is always complete. Attach: resume the live stream, whose overlap with the replay is guaranteed, and drop anything below the cursor. That single comparison is all there is to idempotent replay.
- Explain why the dual write is mandatory: chunks go both to the stream and to the table. Stream only, and the early chunks are gone by reconnect time; table only, and you are polling the database, pushing time-to-first-token from tens to hundreds of milliseconds. The cost is write amplification — hundreds of rows per answer — so production batches the writes, every few dozen chunks or every couple hundred milliseconds.
- Get the protocol detail right: the browser's native event source replays the last id in a request header for you, but model endpoints generally need POST while that API only issues GET, so real frontends hand-roll the parser and must resend the id themselves. Mentioning this proves you have actually wired up the client side.
- Expect: how long do you keep replayable data? Give two bounds — a retention window (per-chunk rows only for runs from the last few hours, then collapsed into one complete message) and a replay cap (beyond N chunks, send the full text once instead of re-enacting it character by character). Without both, that table becomes the largest in the database while 99% of its rows are never read again after ten seconds.
答题要点
- 重连的前提是序号从 0 开始、连续、单调;序号是时间戳或随机 id 就无法续传
- 客户端带回来的是「最后收到」的那一号,服务端要加一再开始,这是唯一的算术也最容易错
- 先从库里回放缺的片段(库一定是全的),再接上还在流动的流,重叠部分靠「小于当前指针一律丢弃」去重
- 片段必须双写:流服务当前挂着的连接,库服务等一下才回来的人;代价是写放大,生产里按批落库
- 必须定保留期与回放上限:过期的执行归档成一整条完整回复,超长回放直接一次性发完整文本
Key points
- Resumption requires a contiguous, monotonic sequence starting at 0; timestamps or random ids make it impossible
- The client reports its last received id, so the server resumes from that id plus one — the single most error-prone line
- Replay the gap from durable storage first, then attach the live stream, discarding anything below the cursor to dedupe the overlap
- Dual-write every chunk: the stream serves currently attached connections, the table serves clients that come back later; batch the writes in production
- Set a retention window and a replay cap — archive old runs into one complete message and send full text instead of re-enacting long replays